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(A) Positional isomerism occurs when the position of a functional group,substituent,or multiple bond changes in the carbon chain.For alkanes,the simpl

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$4$

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(A) Positional isomerism occurs when the position of a functional group,substituent,or multiple bond changes in the carbon chain.For alkanes,the simplest chain to show positional isomerism is $n$-butane $(CH_3-CH_2-CH_2-CH_3)$ and isobutane $(CH_3-CH(CH_3)-CH_3)$,which requires $4$ carbon atoms.For alkenes,the simplest example is but$-1-$ene $(CH_2=CH-CH_2-CH_3)$ and but$-2-$ene $(CH_3-CH=CH-CH_3)$,which also requires $4$ carbon atoms.For alcohols,the simplest example is propan$-1-$ol $(CH_3-CH_2-CH_2-OH)$ and propan$-2-$ol $(CH_3-CH(OH)-CH_3)$,which requires $3$ carbon atoms.However,the question generally refers to the minimum number of carbon atoms required for a hydrocarbon chain to exhibit positional isomerism,which is $4$.

Minimum number of carbon atoms required for a compound to show positional isomerism?

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